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Piano Board => Repertoire => Topic started by: pianoperfmajor on July 10, 2006, 11:09:34 PM

Title: Beethoven Appassionata
Post by: pianoperfmajor on July 10, 2006, 11:09:34 PM

I'm just beginning to learn this piece and I find it very hard to think about in the 12/8 time signature.  How do you think about time signature of this piece to make it a bit more palatable?  Maybe 4/4? 

Title: Re: Beethoven Appassionata
Post by: phil13 on July 11, 2006, 04:47:58 AM

Generally:

2/4, 3/4, 4/4 = simple (2 8th notes for each beat)

6/8, 9/8, 12/8 = compound (3 8th notes for each beat)

Every regular compound time signature is just a simple one with triplets. Thus, 6/8 divides into 2 sets of 3, 9/8 into 3 sets of 3, and 12/8 into 4 sets of 3.

So, yes, specifically, 12/8 = 4 sets of 3 = 4/4

Phil

Title: Re: Beethoven Appassionata
Post by: Kassaa on July 11, 2006, 05:25:22 AM

Quote from: phil13 on July 11, 2006, 04:47:58 AM

Generally:

2/4, 3/4, 4/4 = simple (2 8th notes for each beat)

6/8, 9/8, 12/8 = compound (3 8th notes for each beat)

Every regular compound time signature is just a simple one with triplets. Thus, 6/8 divides into 2 sets of 3, 9/8 into 3 sets of 3, and 12/8 into 4 sets of 3.

So, yes, specifically, 12/8 = 4 sets of 3 = 4/4

Phil

huh? 12/3=4 and 8/3 = 2 ²/³ . Wouldn't 6/4 be more logic?

Title: Re: Beethoven Appassionata
Post by: jre58591 on July 11, 2006, 05:58:10 AM

jsut think of 12/8 as 4/4 with triplets.