Can someone please explain how to prepare and resolve a six four chord? i've been reading theory of harmony and have gotten quite confused.
I understand doubling, 4 part harmony, preparing and resolving 7th chords, and six chords. but i'm reading about six four chords and i'm like, what's the point of all this.
But just to be safe, Beethoven will have us spend another 2 measures pounding G chords.
(firstly, I think you meant I64, V, I?)
V8---------7-------- I 6----5------------- 4----3-------------
Yes I64. However, Aldwell and Schacter (2nd ed) refer to it as a V64. In fact there is an entire chapter covering the use of this chord. It probably has something to do with outlining the resolution of 64-53, and that really the two chords serve as a pair. Saying V64-53 does more to outline the fact that the intent is really to move towards a V chord. It gives more clarity as opposed to I64, V, I; or I64, V, V7, I. Calling it a V64 also alludes to its specific use as a Cadential 64, differentiating it from other functional uses of the 64 chord. An example, a single V with outlines of voice movements:Code: [Select]V8---------7-------- I 6----5------------- 4----3-------------