Help!! counting polyrhythm(9:8) in 4/4

[luna12]

Hello , everyone.

I am learning polyrhythm.
How to count polyrhythm 9:8 in 4/4 ? please see pdf (score)



I understand the 9:8 that we need common denominate 72 and we subdivision 9 into 8 .

But  I don't understand that how come 9:8 takes two beat in 4/4 , so 9:8 two time equal 4 beat ?
Can somebody show me how come ? I am so stuck with this.What do I need to understand first ?
Can somebody explain to me with algebra please ? or is there easy way to understanding this ?

please help

thanks in advance
Lu

[j_menz]

What you've attached isn't a polyrhythm, just a complicated one. A polyrhythm has two (or more going) on at once. 9v8 is not a place to start with polyrhythms anyway.

Just play as is but keep to the beats.

[chopin2015]

If your left hand was written out, it would be in groups. Groups of 8. So, that would be the pulse and 9 would have to occur in the same amount as 8. It would be a little faster than 8. Practice using your hand to keep the pulse and count to 8. Then try to keep the pulse the same and squeeze in 9. The counting will be a little faster sounding...

[ajspiano]

How about thinking of it like this..   if you dont understand what I'm getting at just ask.



Thing is though, the phrasing suggests to me that the composer didn't really feel this in defined pulses or beats. It looks more like, at least in the second half of that bar something that is close to a 5 in 4, and then a straight 4.. at least so far as how it was conceived..  but it would be played rhythmically a bit looser.. as if the 2 subsections just spread the full minim.

I'm not sure if I'm being to bold, but this notations looks like "best way I could notate what I mean, but really its not quite possible to do this in standard notation" ... or in other words, you need an aural translation to really get what he/she means.