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Topic: the most wicked chord in existence.  (Read 2248 times)

Offline Derek

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the most wicked chord in existence.
on: May 13, 2005, 04:38:16 PM
is this not the most wicked chord on the planet?

lowest c
octave c
e above that c
f# above that e
another octave c

Offline Dazzer

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Re: the most wicked chord in existence.
Reply #1 on: May 13, 2005, 04:49:46 PM
why? isn't that just a dim 5th?

the simp sonnsssssssssssssssssssssss

Offline Derek

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Re: the most wicked chord in existence.
Reply #2 on: May 13, 2005, 04:51:55 PM
a diminished 5th with a major third stashed in between it, really low on the piano. it sounds relaly wicked that low.

Offline Dazzer

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Re: the most wicked chord in existence.
Reply #3 on: May 13, 2005, 04:57:17 PM
if that's the case the simpsons must be evil then.

Offline Daevren

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Re: the most wicked chord in existence.
Reply #4 on: May 14, 2005, 12:06:23 PM
The Prometheus chord in F#

Offline BoliverAllmon

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Re: the most wicked chord in existence.
Reply #5 on: May 14, 2005, 07:07:20 PM
just a simple French aug. 6 chord. with the Bb missing.

boliver

Offline raymagini

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Re: the most wicked chord in existence.
Reply #6 on: May 15, 2005, 03:22:06 AM
actually i think it would be an A#

(so then the C and A# make the augmented 6th, C and B flat would be a minor 7th)

Offline BoliverAllmon

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Re: the most wicked chord in existence.
Reply #7 on: May 16, 2005, 05:23:10 PM
actually i think it would be an A#

(so then the C and A# make the augmented 6th, C and B flat would be a minor 7th)

nah think of it as C,E,Gb (not F#), and Bb. Hence the French +6.

Offline Nightscape

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Re: the most wicked chord in existence.
Reply #8 on: May 16, 2005, 06:25:19 PM
There is no augmented sixth in Derek's original chord.  Therefore, it cannot be any type of augmented sixth chord.....  It's the equivalent of saying that C E G is a dominant seventh chord with the Bb omitted.

Derek's chord.... essentially C E F# is not a convential music theory chord.  If enharmonically spelled C E Gb it could be considered a type of triad, but not one likely to be found by itself.  On the other hand, if a piece contained a passage in the Lydian mode on C,  the C E F# could happen all the time, with F# usually being a passing or neighbor tone.  Also, this chord could function well in a whole-tone passage.... I'm you could find it in Debussy or other modern composers.

Offline Rach3

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Re: the most wicked chord in existence.
Reply #9 on: May 16, 2005, 09:52:01 PM
Or, C-E-F# is just a second-inversion half-diminished seventh, with the third omitted. Notation would be vii*4/3   where the asterik replaces the circle with the line through it, which isn't in ASCII

(For a correct usage of this chord, refer to the last measure of the last movement of Prokofiev's last sonata [no. 9, C major])

Quote
nah think of it as C,E,Gb (not F#), and Bb. Hence the French +6.
You're absolutely right, it would have to be a Gb instead of an F#; which is precisely why it doesn't work. If the OP was thinking C E Gb, that would be second-inversion Fr+6 with omitted third, no problem.

Quote
There is no augmented sixth in Derek's original chord.
Actually, +6 would have been from the Gb to the E, it's second inversion. Correctly, it's a half-diminished 7th from F# to E, second inversion. Thirds can be omitted without penalty in seventh chords.
"Never look at the trombones, it only encourages them."
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Offline BoliverAllmon

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Re: the most wicked chord in existence.
Reply #10 on: May 17, 2005, 02:01:40 PM
Or, C-E-F# is just a second-inversion half-diminished seventh, with the third omitted. Notation would be vii*4/3   where the asterik replaces the circle with the line through it, which isn't in ASCII

(For a correct usage of this chord, refer to the last measure of the last movement of Prokofiev's last sonata [no. 9, C major])
You're absolutely right, it would have to be a Gb instead of an F#; which is precisely why it doesn't work. If the OP was thinking C E Gb, that would be second-inversion Fr+6 with omitted third, no problem.
 Actually, +6 would have been from the Gb to the E, it's second inversion. Correctly, it's a half-diminished 7th from F# to E, second inversion. Thirds can be omitted without penalty in seventh chords.

I guess it would be easier to determine which chord it is by looking at the sheets and seeing what proceeds and comes after the chord. the half dim. 7th chord is a real possibility.

Offline lostinidlewonder

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Re: the most wicked chord in existence.
Reply #11 on: May 18, 2005, 12:06:39 AM
You have to love how Scriabin uses the Mystical Chords and utilises the 4ths through his writing.
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Offline Derek

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Re: the most wicked chord in existence.
Reply #12 on: May 18, 2005, 12:21:41 AM
I should have mentioned earlier ....I also find this chord most wicked when its played very quietly, and then play a melody with even more dissonance up above, but not far above it......sounds absolutely menacing  >:(

Offline jbmajor

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Re: the most wicked chord in existence.
Reply #13 on: May 20, 2005, 04:37:05 AM
The most wicked I've heard is something like a B sus2 with a double octave, all on the lowest register of the keyboard. 

I have no idea the correct naming of it, but this is it:

Lowest B octave + C# + F# +B +C#, all in a row.  The highest note is the C# an octave down from where middle C(#) is. 

You can hear this in Rach's Bminor prelude, op. 32 no. 10. 

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