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Topic: Mathematical fun with Music  (Read 3818 times)

Offline chopinetta

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Re: Mathematical fun with Music
Reply #50 on: May 24, 2005, 01:37:26 AM
well, I have to agree with cadenz. there are 10 possible arrangements of the repeated notes. why 10? simply put... C(5,2) by counting how many pairs are possible with 5 notes.

so taking the 1st scenario w/o repetitions. P(88,5)
2nd scenario w/ repetitions. 10P(88,4)

P(88,5) + 10P(88,4) = 5,260,743,840 possible motives. this is probably the "rightest" one so far.
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