Dude, just ask your teacher. It's not gay to ask a teacher for help. Sheesh! Grow up!

Because some of us, I are too afraid to approach our teachers.

gayGrow up!

I tutor calc. and stats. If you need help feel free to message me or just post here,

Favorite three people on piano street:1. lloyd_cdb2. J Menz3. Everyone else

What?! if you're going to assert that we are the same person you have to rate us (me) equally. I'm hurt.

I think that J Menz is the original personality. Besides, I like that one better.

Name: j_menzPosts: 2064 (7.759 per day)Position: PS Silver MemberDate Registered: January 19, 2012, 12:21:22 AMName: ajspianoPosts: 1705 (5.059 per day)Position: PS Gold MemberDate Registered: November 09, 2011, 12:25:27 AM..now what are you going to do to support your pathetic arguement?

Oh, and see your teacher and ask the questions you want. It's their job, and you may well be surprised how helpful they are.

Nah dude, those guys are scary.

No, they're not. They are teachers, who want you to learn and believe they can help you do that.They will be scary if you don't let them know that you have not understood something and just keep turning in wrong answers. They will be scary if you just don't try. They won't be scary if you ask for their help.

I mean I'm willing to help out but wouldn't calcchat.com be a better place to find help? All of the kids in our class use calcchat. Perhaps a little too much..

Noooooooooooooo you don't understand! They're sooooo freaking scary!Regular teachers are okay. Honors and AP teachers are like freaking monsters!

I suspect I have had more, and more advanced, teachers than you, so I do not accept that I do not understand.More advanced teachers are used to more advanced students, and advanced students ask if they do not understand something. In many ways, it is indeed how they became advanced students.

I think they're really mean and if you don't understand something they'll get mad at you if it's like really basic.

I don't like those teachers because I think they're really mean and if you don't understand something they'll get mad at you if they think it's basic.I've known this from personal experience throughout my high school career. So I've learned to avoid them.And even in class, if the teacher asks the student body something, I don't say a word! Because that one time you're wrong you feel like everyone's flaming you in their heads.

You mean as in something you really should have asked about earlier, but didn't?

but the guy who said he's a tutor in calc sounds legitimate.

I think fftransform's actual profession is mathematician.. I vaguely remember him saying that once, and he certainly used some fairly technical maths terminology to have a crack at me in a thread a few months back..

Let f be the function defined by f(x) = sin^2x - sinx for x is between 0 and 3pi/2a. find the x intercepts of fb. write the equation of any horizontal tangents of fc. find the intervals on which f is incereasingd. sketch an accurate graph of f'(x) and explain how that graph can help you answer (c).

indeed, quite resourceful! Have fun, Rach_forevs

not sure if you've gotten the rest of it yet:b) horizontal tangents exist where the derivative of the equation is equal to zero.f(x) = sin(x)^2 - sin(x)f'(x) = sin(2x) - cos(x)solve for f'(x) = 0sin(2x) - cos(x) = 0sin(2x) = cos(x): since sin (2x) = 2sin(x)cos(x),2sin(x)cos(x) - cos(x) = 0cos(x)[2sin(x) - 1] = 0so cos(x) = 0, and/or 2sin(x) - 1 = 0, between 0 and 3pi/2pi/2, 3pi/2 ............. pi/6, 5pi/6c) The line is increasing at points in which f'(x) > 0. I'm not sure if there is a better way to do this, but since the tangential lines are zero at (pi/6, pi/2, 5pi/6, 3pi/2), just pick an arbitrary number between each of these intervals (as well as the 0 to pi/6 interval). If the result is positive, that is an increasing interval.d) every x intercept of f'(x) is a horizontal tangent of the original equation which you found in b). f'(x) represents the rate of change of the original equation, so anywhere the graph of f'(x) is above y=0 the original function is increasing.

Didn't you say you were in college? How old are you?I think the derivative is wrong. Wouldn't it be f'(x)=2sinxcosx-cosx?

TALK TO YOUR TEACHER

Just to back Rach4 on why he's scared of talking to his teacher, I've had negative experiences with talking to teachers. I once spoke to a Japanese teacher about my test (59%) only to have her make me cry. She communicated (but didn't say explicitly) to get the hell out of her office, I'm' stupid, and I'm wasting her time. I did all I could not to burst into tears while sitting in the chair as she was staring me down. A short while later, as I was driving to work, I told my co-worker what happened and my eyes exploded. Some people just shouldn't be teachers.

I know it's probably too late at this point, but can you switch teachers? Or maybe if you're a junior you can find the teachers that have great reputations and try and get in their class for next year?

I think the derivative is wrong. Wouldn't it be f'(x)=2sinxcosx-cosx? Either way, you need a cosx somewhere in that first term.

God damn it she called my parents and told me to come see her 7:30 every morning!

Evidently she cares about you and your results. Make ther most of the opportunity.

This is gonna be terrible...